0.002-1+x^2-0.002*x=0

Solution for 0.002-1+x^2-0.002*x=0 equation:

0.002-1+x^2-0.002x=0

We add all the numbers together, and all the variables

x^2-0.002x-0.998=0

a = 1; b = -0.002; c = -0.998;
Δ = b2-4ac
Δ = -0.0022-4·1·(-0.998)
Δ = 3.992004
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.002)-\sqrt{3.992004}}{2*1}=\frac{0.002-\sqrt{3.992004}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.002)+\sqrt{3.992004}}{2*1}=\frac{0.002+\sqrt{3.992004}}{2}
$